Integrand size = 30, antiderivative size = 175 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=-\frac {c}{9 a^2 x^9}+\frac {2 b c-a d}{6 a^3 x^6}-\frac {3 b^2 c-2 a b d+a^2 e}{3 a^4 x^3}-\frac {b^3 c-a b^2 d+a^2 b e-a^3 f}{3 a^4 \left (a+b x^3\right )}-\frac {\left (4 b^3 c-3 a b^2 d+2 a^2 b e-a^3 f\right ) \log (x)}{a^5}+\frac {\left (4 b^3 c-3 a b^2 d+2 a^2 b e-a^3 f\right ) \log \left (a+b x^3\right )}{3 a^5} \]
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Time = 0.14 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {1835, 1634} \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=\frac {2 b c-a d}{6 a^3 x^6}-\frac {c}{9 a^2 x^9}-\frac {a^2 e-2 a b d+3 b^2 c}{3 a^4 x^3}+\frac {\log \left (a+b x^3\right ) \left (a^3 (-f)+2 a^2 b e-3 a b^2 d+4 b^3 c\right )}{3 a^5}-\frac {\log (x) \left (a^3 (-f)+2 a^2 b e-3 a b^2 d+4 b^3 c\right )}{a^5}-\frac {a^3 (-f)+a^2 b e-a b^2 d+b^3 c}{3 a^4 \left (a+b x^3\right )} \]
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Rule 1634
Rule 1835
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {c+d x+e x^2+f x^3}{x^4 (a+b x)^2} \, dx,x,x^3\right ) \\ & = \frac {1}{3} \text {Subst}\left (\int \left (\frac {c}{a^2 x^4}+\frac {-2 b c+a d}{a^3 x^3}+\frac {3 b^2 c-2 a b d+a^2 e}{a^4 x^2}+\frac {-4 b^3 c+3 a b^2 d-2 a^2 b e+a^3 f}{a^5 x}-\frac {b \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right )}{a^4 (a+b x)^2}-\frac {b \left (-4 b^3 c+3 a b^2 d-2 a^2 b e+a^3 f\right )}{a^5 (a+b x)}\right ) \, dx,x,x^3\right ) \\ & = -\frac {c}{9 a^2 x^9}+\frac {2 b c-a d}{6 a^3 x^6}-\frac {3 b^2 c-2 a b d+a^2 e}{3 a^4 x^3}-\frac {b^3 c-a b^2 d+a^2 b e-a^3 f}{3 a^4 \left (a+b x^3\right )}-\frac {\left (4 b^3 c-3 a b^2 d+2 a^2 b e-a^3 f\right ) \log (x)}{a^5}+\frac {\left (4 b^3 c-3 a b^2 d+2 a^2 b e-a^3 f\right ) \log \left (a+b x^3\right )}{3 a^5} \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 160, normalized size of antiderivative = 0.91 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=\frac {-\frac {2 a^3 c}{x^9}-\frac {3 a^2 (-2 b c+a d)}{x^6}-\frac {6 a \left (3 b^2 c-2 a b d+a^2 e\right )}{x^3}+\frac {6 a \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right )}{a+b x^3}+18 \left (-4 b^3 c+3 a b^2 d-2 a^2 b e+a^3 f\right ) \log (x)+6 \left (4 b^3 c-3 a b^2 d+2 a^2 b e-a^3 f\right ) \log \left (a+b x^3\right )}{18 a^5} \]
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Time = 1.50 (sec) , antiderivative size = 169, normalized size of antiderivative = 0.97
method | result | size |
default | \(-\frac {c}{9 a^{2} x^{9}}-\frac {a d -2 b c}{6 a^{3} x^{6}}-\frac {a^{2} e -2 a b d +3 b^{2} c}{3 a^{4} x^{3}}+\frac {\left (f \,a^{3}-2 a^{2} b e +3 a \,b^{2} d -4 b^{3} c \right ) \ln \left (x \right )}{a^{5}}-\frac {b \left (\frac {\left (f \,a^{3}-2 a^{2} b e +3 a \,b^{2} d -4 b^{3} c \right ) \ln \left (b \,x^{3}+a \right )}{b}-\frac {a \left (f \,a^{3}-a^{2} b e +a \,b^{2} d -b^{3} c \right )}{b \left (b \,x^{3}+a \right )}\right )}{3 a^{5}}\) | \(169\) |
norman | \(\frac {-\frac {c}{9 a}-\frac {\left (3 a d -4 b c \right ) x^{3}}{18 a^{2}}-\frac {\left (2 a^{2} e -3 a b d +4 b^{2} c \right ) x^{6}}{6 a^{3}}+\frac {b \left (-f \,a^{3}+2 a^{2} b e -3 a \,b^{2} d +4 b^{3} c \right ) x^{12}}{3 a^{5}}}{x^{9} \left (b \,x^{3}+a \right )}+\frac {\left (f \,a^{3}-2 a^{2} b e +3 a \,b^{2} d -4 b^{3} c \right ) \ln \left (x \right )}{a^{5}}-\frac {\left (f \,a^{3}-2 a^{2} b e +3 a \,b^{2} d -4 b^{3} c \right ) \ln \left (b \,x^{3}+a \right )}{3 a^{5}}\) | \(172\) |
risch | \(\frac {\frac {\left (f \,a^{3}-2 a^{2} b e +3 a \,b^{2} d -4 b^{3} c \right ) x^{9}}{3 a^{4}}-\frac {\left (2 a^{2} e -3 a b d +4 b^{2} c \right ) x^{6}}{6 a^{3}}-\frac {\left (3 a d -4 b c \right ) x^{3}}{18 a^{2}}-\frac {c}{9 a}}{x^{9} \left (b \,x^{3}+a \right )}+\frac {\ln \left (x \right ) f}{a^{2}}-\frac {2 \ln \left (x \right ) b e}{a^{3}}+\frac {3 \ln \left (x \right ) b^{2} d}{a^{4}}-\frac {4 \ln \left (x \right ) b^{3} c}{a^{5}}-\frac {\ln \left (b \,x^{3}+a \right ) f}{3 a^{2}}+\frac {2 \ln \left (b \,x^{3}+a \right ) b e}{3 a^{3}}-\frac {\ln \left (b \,x^{3}+a \right ) b^{2} d}{a^{4}}+\frac {4 \ln \left (b \,x^{3}+a \right ) b^{3} c}{3 a^{5}}\) | \(200\) |
parallelrisch | \(\frac {-6 x^{6} a^{4} b e +9 x^{6} a^{3} b^{2} d -12 x^{6} a^{2} b^{3} c -3 x^{3} a^{4} b d -72 \ln \left (x \right ) x^{12} b^{5} c +24 \ln \left (b \,x^{3}+a \right ) x^{12} b^{5} c -2 a^{4} b c +4 a^{3} b^{2} c \,x^{3}-36 \ln \left (x \right ) x^{12} a^{2} b^{3} e +54 \ln \left (x \right ) x^{12} a \,b^{4} d -6 \ln \left (b \,x^{3}+a \right ) x^{12} a^{3} b^{2} f +6 x^{9} a^{4} b f -12 x^{9} a^{3} b^{2} e +18 x^{9} a^{2} b^{3} d -24 x^{9} a \,b^{4} c -36 \ln \left (x \right ) x^{9} a^{3} b^{2} e +54 \ln \left (x \right ) x^{9} a^{2} b^{3} d -72 \ln \left (x \right ) x^{9} a \,b^{4} c -6 \ln \left (b \,x^{3}+a \right ) x^{9} a^{4} b f +12 \ln \left (b \,x^{3}+a \right ) x^{9} a^{3} b^{2} e -18 \ln \left (b \,x^{3}+a \right ) x^{9} a^{2} b^{3} d +24 \ln \left (b \,x^{3}+a \right ) x^{9} a \,b^{4} c +18 \ln \left (x \right ) x^{12} a^{3} b^{2} f +12 \ln \left (b \,x^{3}+a \right ) x^{12} a^{2} b^{3} e +18 \ln \left (x \right ) x^{9} a^{4} b f -18 \ln \left (b \,x^{3}+a \right ) x^{12} a \,b^{4} d}{18 a^{5} b \,x^{9} \left (b \,x^{3}+a \right )}\) | \(383\) |
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Time = 0.31 (sec) , antiderivative size = 261, normalized size of antiderivative = 1.49 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=-\frac {6 \, {\left (4 \, a b^{3} c - 3 \, a^{2} b^{2} d + 2 \, a^{3} b e - a^{4} f\right )} x^{9} + 3 \, {\left (4 \, a^{2} b^{2} c - 3 \, a^{3} b d + 2 \, a^{4} e\right )} x^{6} + 2 \, a^{4} c - {\left (4 \, a^{3} b c - 3 \, a^{4} d\right )} x^{3} - 6 \, {\left ({\left (4 \, b^{4} c - 3 \, a b^{3} d + 2 \, a^{2} b^{2} e - a^{3} b f\right )} x^{12} + {\left (4 \, a b^{3} c - 3 \, a^{2} b^{2} d + 2 \, a^{3} b e - a^{4} f\right )} x^{9}\right )} \log \left (b x^{3} + a\right ) + 18 \, {\left ({\left (4 \, b^{4} c - 3 \, a b^{3} d + 2 \, a^{2} b^{2} e - a^{3} b f\right )} x^{12} + {\left (4 \, a b^{3} c - 3 \, a^{2} b^{2} d + 2 \, a^{3} b e - a^{4} f\right )} x^{9}\right )} \log \left (x\right )}{18 \, {\left (a^{5} b x^{12} + a^{6} x^{9}\right )}} \]
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Timed out. \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=\text {Timed out} \]
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Time = 0.21 (sec) , antiderivative size = 181, normalized size of antiderivative = 1.03 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=-\frac {6 \, {\left (4 \, b^{3} c - 3 \, a b^{2} d + 2 \, a^{2} b e - a^{3} f\right )} x^{9} + 3 \, {\left (4 \, a b^{2} c - 3 \, a^{2} b d + 2 \, a^{3} e\right )} x^{6} + 2 \, a^{3} c - {\left (4 \, a^{2} b c - 3 \, a^{3} d\right )} x^{3}}{18 \, {\left (a^{4} b x^{12} + a^{5} x^{9}\right )}} + \frac {{\left (4 \, b^{3} c - 3 \, a b^{2} d + 2 \, a^{2} b e - a^{3} f\right )} \log \left (b x^{3} + a\right )}{3 \, a^{5}} - \frac {{\left (4 \, b^{3} c - 3 \, a b^{2} d + 2 \, a^{2} b e - a^{3} f\right )} \log \left (x^{3}\right )}{3 \, a^{5}} \]
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Time = 0.28 (sec) , antiderivative size = 269, normalized size of antiderivative = 1.54 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=-\frac {{\left (4 \, b^{3} c - 3 \, a b^{2} d + 2 \, a^{2} b e - a^{3} f\right )} \log \left ({\left | x \right |}\right )}{a^{5}} + \frac {{\left (4 \, b^{4} c - 3 \, a b^{3} d + 2 \, a^{2} b^{2} e - a^{3} b f\right )} \log \left ({\left | b x^{3} + a \right |}\right )}{3 \, a^{5} b} - \frac {4 \, b^{4} c x^{3} - 3 \, a b^{3} d x^{3} + 2 \, a^{2} b^{2} e x^{3} - a^{3} b f x^{3} + 5 \, a b^{3} c - 4 \, a^{2} b^{2} d + 3 \, a^{3} b e - 2 \, a^{4} f}{3 \, {\left (b x^{3} + a\right )} a^{5}} + \frac {44 \, b^{3} c x^{9} - 33 \, a b^{2} d x^{9} + 22 \, a^{2} b e x^{9} - 11 \, a^{3} f x^{9} - 18 \, a b^{2} c x^{6} + 12 \, a^{2} b d x^{6} - 6 \, a^{3} e x^{6} + 6 \, a^{2} b c x^{3} - 3 \, a^{3} d x^{3} - 2 \, a^{3} c}{18 \, a^{5} x^{9}} \]
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Time = 9.65 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.00 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{10} \left (a+b x^3\right )^2} \, dx=\frac {\ln \left (b\,x^3+a\right )\,\left (-f\,a^3+2\,e\,a^2\,b-3\,d\,a\,b^2+4\,c\,b^3\right )}{3\,a^5}-\frac {\frac {c}{9\,a}+\frac {x^9\,\left (-f\,a^3+2\,e\,a^2\,b-3\,d\,a\,b^2+4\,c\,b^3\right )}{3\,a^4}+\frac {x^3\,\left (3\,a\,d-4\,b\,c\right )}{18\,a^2}+\frac {x^6\,\left (2\,e\,a^2-3\,d\,a\,b+4\,c\,b^2\right )}{6\,a^3}}{b\,x^{12}+a\,x^9}-\frac {\ln \left (x\right )\,\left (-f\,a^3+2\,e\,a^2\,b-3\,d\,a\,b^2+4\,c\,b^3\right )}{a^5} \]
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